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How do you solve #3/7=(x-2)/6#?

Answer 1

Eva Adamson

#x=32/7#

Solve #3/7=(x-2)/6#

Multiply both sides by #6#.

#3/7xx6=x-2#

Simplify.

#(3xx6)/7=x-2#

#18/7=x-2#

Multiply both sides by #7#.

#18=7(x-2)#

Expand.

#18=7x-14#

Add #14# to both sides.

#18+14=7x#

Simplify.

#32=7x#

Divide both sides by #7#.

#32/7=x#

Switch sides.

#x=32/7#

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Answer 2

Kennedy Adams

To solve the equation 3/7 = (x-2)/6, you can cross-multiply. Multiply 3 by 6 to get 18, and multiply 7 by (x-2) to get 7x-14. Set these two products equal to each other: 18 = 7x-14. Add 14 to both sides of the equation: 18+14 = 7x-14+14. Simplify: 32 = 7x. Divide both sides of the equation by 7: 32/7 = 7x/7. Simplify: 4.57 = x. Therefore, x is approximately equal to 4.57.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.