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How do you solve #-3(4x+3)+4(6x+1)=43#?

Answer 1

Julia Adams

#x=4#

#-3(4x+3)+4(6x+1)=43#

Taking the brackets off:

#-12x-9+24x+4=43#

Mix similar terms together:

#-12x+24x-9+4=43#

#12x-5=43#

To isolate the x, add five:

#12x-5+5=43+5#

#12x=48#

To fully isolate the x, divide both sides by 12:

#(cancel(12)x)/cancel12=48/12#

#x=4#

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Answer 2

Jameson Allen

To solve the equation -3(4x + 3) + 4(6x + 1) = 43, follow these steps:

Distribute the terms inside the parentheses: -12x - 9 + 24x + 4 = 43
Combine like terms: -12x + 24x - 9 + 4 = 43 12x - 5 = 43
Add 5 to both sides of the equation: 12x = 48
Divide both sides by 12: x = 4

Therefore, the solution to the equation is x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.