Home > Algebra > Equations with Variables on Both Sides

How do you solve #3(4x-2)=-2(-6x+3)#?

Answer 1

Eli Assouline

#x# = any value

multiplying the brackets by two:

#3(4x-2)=12x-6#

#12x-6=-2(-6x+3)#

#-2(-6x+3)=12x-6#

#12x-6=12x-6#

Since both equations are the same, #x# could have any value and still satisfy this system of equations.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Avery Alexander

To solve the equation 3(4x - 2) = -2(-6x + 3), you would first distribute the terms inside the parentheses. Then, combine like terms and solve for "x". The solution is x = 1.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.