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How do you solve #3(3x+1)-(x-1)=6(x+10)#?

Answer 1

Avery Alexander

#x = 28#

#3 ( 3x+1) - (x-1) = 6 (x+10)#

#3 * ( 3x)+ 3 * (1) - x + 1 = 6 * (x) + 6 * (10)#

#9x+ 3 - x + 1 = 6 x + 60#

#9x - x + 3 + 1 = 6 x + 60#

#8x + 4 = 6 x + 60#

#8x -6x = 60 - 4#

#2x = 56#

#x = 56/2#

#x = 28#

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Answer 2

Hazel Anglin

To solve the equation 3(3x + 1) - (x - 1) = 6(x + 10), first distribute the terms inside the parentheses, then combine like terms, and finally isolate the variable on one side of the equation. Here are the steps:

Distribute the terms: 9x + 3 - x + 1 = 6x + 60
Combine like terms: 9x - x + 3 + 1 = 6x + 60 8x + 4 = 6x + 60
Subtract 6x from both sides: 8x - 6x + 4 = 6x - 6x + 60 2x + 4 = 60
Subtract 4 from both sides: 2x + 4 - 4 = 60 - 4 2x = 56
Divide both sides by 2: 2x / 2 = 56 / 2 x = 28

Therefore, the solution to the equation is x = 28.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.