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How do you solve #3( 3m - 2) = 2( 2m + 3)#?

Answer 1

Ethan Adkins

#m=12/5#

Multiply the number before the parenthesis by each number inside the parenthesis using the distributive property.

#3*3m= 9m#

#3 * (-2)=6#

#2*2m=4m#

#2*3=6#

The current equation is

#9m-6=4m+6#

The next step is to add #6# on the left side and on the right side. This will get rid of the #-6# on the left side. Your new equation is

#9m=4m+12#

Then you are going to subtract #4m# from both sides. This will give you

#5m=12#

Divide both sides by #5#

#m = 12/5#

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Answer 2

Kennedy Adams

To solve the equation 3(3m - 2) = 2(2m + 3):

Distribute the terms inside the parentheses: 9m - 6 = 4m + 6
Move all terms involving 'm' to one side and constants to the other side: 9m - 4m = 6 + 6
Combine like terms: 5m = 12
Divide both sides by 5 to solve for 'm': m = 12/5

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Answer from HIX Tutor

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