How do you solve #3/2y-y=4+.5y#?

Answer 1

See a solution process below:

First, convert #3/2# to:
#3/2 = (2 + 1)/2 = 2/2 + 1/2 = 1 + 1/2 = 1 + 0.5 = 1.5#

We can rephrase the issue as follows:

#1.5y - y = 4 + 0.5y#

Next, on the left side of the equation, we can combine terms that are similar:

#1.5y - 1y = 4 + 0.5y#
#(1.5 - 1)y = 4 + 0.5y#
#0.5y = 4 + 0.5y#
Now, we can subtract #color(red)(0.5y)# from each side of the equation to show there is no solution:
#0.5y - color(red)(0.5y) = 4 + 0.5y - color(red)(0.5y)#
#0 = 4 + 0#
#0 != 4#
Because #0# is obviously not equal to #4# there is no solution for this problem
Or, the solution is the null or empty set: #{O/}#
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Answer 2

No solutions

Since #3/2# and #1.5# are equivalent, we can rewrite our equation as
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Answer 3

To solve the equation ( \frac{3}{2}y - y = 4 + 0.5y ), follow these steps:

  1. Combine like terms on both sides of the equation.
  2. Simplify the equation by performing arithmetic operations.
  3. Isolate the variable ( y ) on one side of the equation.
  4. Solve for ( y ) by dividing both sides of the equation by the coefficient of ( y ).
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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