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How do you solve #3( 2x + 3x + 2) = - 4x + 124#?

Answer 1

#x = 118/19#

First, expand by multiplying #3# by every term in the brackets. Then group together the terms with #x# in them and group the terms without #x#s in them together.

Finally, divide the number in front of the #x# by the number on the other side to solve for #x#.

#3 (2x + 3x + 2) = -4x + 124#

#3*2x + 3*3x + 3*2 = -4x + 124#

#6x + 9x + 6 = -4x + 124#

#15x + 6 = -4x + 124#

#15x + 4x = 124 - 6#

#19x = 118#

#x = 118/19 = 6.21#

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Answer 2

Eva Adamson

To solve the equation 3(2x + 3x + 2) = -4x + 124:

Distribute the 3 on the left side: 6x + 9x + 6 = -4x + 124
Combine like terms on both sides: 15x + 6 = -4x + 124
Move all the x terms to one side and constants to the other: 15x + 4x = 124 - 6
Simplify both sides: 19x = 118
Solve for x: x = 118 / 19
Simplify the fraction: x = 6.21 (rounded to two decimal places)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.