How do you solve #(3/2)(x+8) = 6x#?

Answer 1

The solution is the usual approach to algebra with order of operations. See the explanation below. The solution is #x=8/3#.

Take #3x# away from both sides.
#24 is equivalent to 9x#

Turn the sequence around:

#9x=24#

By 9, divide both sides.

#x=24/9 = 8/3#

(You can verify that this is true (i.e., that both sides are equal) by entering it into the original equation.)

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Answer 2

To solve (3/2)(x+8) = 6x, first distribute (3/2) across (x+8) to get 3/2x + 3/28 = 6x. Then simplify the equation to get 3x + 12 = 6x. Next, subtract 3x from both sides to get 12 = 3x. Finally, divide both sides by 3 to solve for x, which gives x = 4.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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