How do you solve #3- 2( 5x - 4) > - 9# and #3x > - 4( x - 2)#?

Answer 1

#3-2(5x-4)> -9# ----------------- #3x> -4(x-2)#
#x<2# -----------------------------------#x>8/7#

Ok so the first one #3-2(5x-4)# First we distribute the #-2# giving us #3-10x+8> -9#
We now combine like terms on the left side #11-10x> -9#
Subtract 11 on both sides giving us #-10x> -20#
We now divide by #-10# on both sides. REMEMBER: When dividing by a negative the sign always turn to the other side.
#(-10x)/(-10)< -20/(-10)#
#x<2#
Ok now the second one. First we distribute the #-4# giving us #3x> -4x+8#
Now we add #4x# on both sides giving us #7x>8#
Now we divide #7# on both sides #(7x)/7>8/7#
#x>8/7#
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Answer 2
To solve the inequalities: 1. 3 - 2(5x - 4) > -9: Distribute the -2 inside the parentheses: 3 - 10x + 8 > -9. Combine like terms: -10x + 11 > -9. Subtract 11 from both sides: -10x > -20. Divide both sides by -10 (remember to flip the inequality when dividing by a negative number): x < 2. 2. 3x > -4(x - 2): Distribute the -4 inside the parentheses: 3x > -4x + 8. Add 4x to both sides: 7x > 8. Divide both sides by 7: x > 8/7. Therefore, the solutions are x < 2 and x > 8/7.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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