Home > Algebra > Multi-Step Equations with Like Terms

How do you solve #3(1+x)=2[3(x+2)-(x+1)]#?

Answer 1

Savannah Anderson

#x=-7#

Start by removing the brackets - in the term on the right, start inside the square brackets first.

#3(1+x)=2[3(x+2)-(x+1)]#

#3 + 3x= 2[3x+6 -x-1]#

#3+3x = 2(2x+5)#

#3 +3x = 4x +10#

#3-10 = 4x-3x#

#-7 = x#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Kennedy Adams

To solve the equation 3(1+x)=2[3(x+2)-(x+1)], you first distribute the terms inside the brackets and then combine like terms on each side of the equation. Here are the steps:

Distribute 2 inside the brackets on the right side: 3(1+x) = 2[3(x+2) - (x+1)] becomes: 3(1+x) = 2[3x + 6 - x - 1]
Simplify inside the brackets on the right side: 3(1+x) = 2[2x + 5]
Distribute 3 and 2 inside the brackets: 3(1+x) = 4x + 10
Distribute 3 to 1 and x: 3 + 3x = 4x + 10
Subtract 3x from both sides: 3 = x + 10
Subtract 10 from both sides: -7 = x

So the solution to the equation is x = -7.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.