How do you solve #2z+6z-19=-57#?

Answer 1

#color(blue)(z= -19/4#

#2z+6z−19 = -57#
#8z−19 = -57#
#8z = -57+19#
#8z= -38#
#z= -38/8#
#color(blue)(z= -19/4#
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Answer 2

To solve the equation 2z + 6z - 19 = -57, you first combine like terms on the left side of the equation. This yields 8z - 19 = -57. Then, you add 19 to both sides of the equation to isolate the variable term. This gives you 8z = -38. Finally, you divide both sides of the equation by 8 to solve for z, which results in z = -38/8, or z = -4.5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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