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How do you solve #2z^2 - 3 = -5z#?

Answer 1

Nathan Axel

All that's here is a hidden quadratic

You must realize that moving the #-5z# would make a quadratic equation

So we have #2z^2 + 5z - 3#

We are now only using the quadratic formula.

#(-5 +- sqrt(25 - 4*2*-3))/4#

#(-5 +- sqrt(49)) / 4#

#(-5 +- 7 ) / 4#

Thus, z = 1/2 or z = -3 are our options.

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Answer 2

Genesis Allen

To solve the equation 2z^2 - 3 = -5z, follow these steps:

Move all terms to one side of the equation to set it to zero: 2z^2 + 5z - 3 = 0.
Use the quadratic formula to solve for z: z = (-b ± √(b^2 - 4ac)) / (2a), where a = 2, b = 5, and c = -3.
Substitute the values of a, b, and c into the quadratic formula and solve for z.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.