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How do you solve #2z^2 - 10z = -12#?

Answer 1

2 and 3

#y = 2z^2 - 10z + 12 = 0# Use the improved quadratic formula in graphic form (Socratic Search) #D = d^2 = b^2 - 4ac = 100 - 96 = 4# --> #d = +- 2# There are 2 real roots: #x = -b/(2a) +- d/(2a) = 10/4 +- 2/4# #x = 5/2 +- 1/2 = (5 +- 1)/2 =# #x1 = 6/2 = 3# and #x2 = 4/2 = 2#

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Answer 2

Nathan Axel

To solve the equation 2z^2 - 10z = -12, follow these steps:

Move all terms to one side to set the equation equal to zero: 2z^2 - 10z + 12 = 0
Factor out any common factors: 2(z^2 - 5z + 6) = 0
Factor the quadratic expression inside the parentheses: 2(z - 2)(z - 3) = 0
Apply the zero-product property: Set each factor equal to zero: z - 2 = 0 or z - 3 = 0
Solve each equation for z: For z - 2 = 0: z = 2

For z - 3 = 0: z = 3

Therefore, the solutions to the equation 2z^2 - 10z = -12 are z = 2 and z = 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.