How do you solve #2y^2+6=y^2#?
Take the square root of both sides.
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To solve the equation 2y^2 + 6 = y^2:
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Subtract y^2 from both sides: 2y^2 + 6 - y^2 = y^2 - y^2 y^2 + 6 = 0
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Subtract 6 from both sides: y^2 + 6 - 6 = 0 - 6 y^2 = -6
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Take the square root of both sides: √(y^2) = √(-6) y = ±√(-6)
Since the square root of a negative number is imaginary, there are no real solutions to this equation. The solutions are complex numbers: y = ±√(6)i.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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