How do you solve 2x+y=5 and x-y=1?
In this case we have a perfect scenario because the y terms are additive inverses. When the two equations are added, the y terms will add to 0.
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To solve the system of equations 2x + y = 5 and x - y = 1, you can use the method of substitution or elimination.
Using substitution, solve one of the equations for either x or y, and then substitute that expression into the other equation to solve for the remaining variable. For example, from the second equation x - y = 1, you can solve for x to get x = y + 1. Substitute this expression for x into the first equation:
2(y + 1) + y = 5 2y + 2 + y = 5 3y + 2 = 5 3y = 3 y = 1
Now that you have found y, substitute this value back into the equation x = y + 1 to find x:
x = 1 + 1 x = 2
So, the solution to the system of equations is x = 2 and y = 1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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