How do you solve 2x-y=-1 and 3x+2y=-5?
x = -1
y = -1
Three times two times y = - five --------------(2) and two times x - y = -one (1)
Solve equation (1) so that y = 1 + 2x and y-y = - 1 - 2x.
Enter y = 1 + 2x in the formula (2).
enter the formula (1) with the value x = -1.
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To solve the system of equations 2x - y = -1 and 3x + 2y = -5, you can use the method of substitution or elimination. Here, I'll demonstrate using the method of elimination:
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Multiply the first equation by 2 to make the coefficients of y in both equations equal:
- Equation 1 becomes 4x - 2y = -2
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Now, we have:
- Equation 1: 4x - 2y = -2
- Equation 2: 3x + 2y = -5
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Add the two equations together to eliminate y:
- (4x - 2y) + (3x + 2y) = -2 + (-5)
- 4x - 2y + 3x + 2y = -2 - 5
- 7x = -7
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Solve for x:
- Divide both sides by 7: x = -1
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Substitute the value of x back into either equation to solve for y. Let's use Equation 1:
- 2(-1) - y = -1
- -2 - y = -1
- Subtract -2 from both sides: -y = -1 + 2
- -y = 1
- Multiply both sides by -1 to isolate y: y = -1
So, the solution to the system of equations is x = -1 and y = -1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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