# How do you solve #(2x)/(x-4)=8/(x-4)+3#?

No solution!

First, observe that 4 (division by zero) is not a solution.

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The equation is unsolvable.

We have:

Enlarge the parentheses.

This results in:

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To solve the equation (2x)/(x-4)=8/(x-4)+3, we can start by multiplying both sides of the equation by (x-4) to eliminate the denominators. This gives us 2x = 8 + 3(x-4). Simplifying further, we have 2x = 8 + 3x - 12. Combining like terms, we get 2x - 3x = -4. Simplifying again, we have -x = -4. Finally, dividing both sides of the equation by -1, we find x = 4.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- If y varies directly as x and inversely as the square of z and y=1/6 when x=20 and z =6, how do you find y when x = 14 and z=5?

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