How do you solve #2x + sqrt(x+1) = 8#?
By signing up, you agree to our Terms of Service and Privacy Policy
To solve the equation 2x + sqrt(x+1) = 8, you can follow these steps:

Start by isolating the square root term. Subtract 2x from both sides of the equation: sqrt(x+1) = 8  2x

Square both sides of the equation to eliminate the square root: (sqrt(x+1))^2 = (8  2x)^2 x + 1 = (8  2x)^2

Expand the right side of the equation: x + 1 = 64  32x + 4x^2

Rearrange the equation to form a quadratic equation: 4x^2  32x + (1  64) = 0 4x^2  32x  63 = 0

Solve the quadratic equation. You can use factoring, completing the square, or the quadratic formula. In this case, the quadratic equation can be factored as: (2x + 1)(2x  63) = 0

Set each factor equal to zero and solve for x: 2x + 1 = 0 or 2x  63 = 0

Solve for x in each equation: For 2x + 1 = 0: 2x = 1 x = 1/2
For 2x  63 = 0: 2x = 63 x = 63/2
Therefore, the solutions to the equation 2x + sqrt(x+1) = 8 are x = 1/2 and x = 63/2.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
 98% accuracy study help
 Covers math, physics, chemistry, biology, and more
 Stepbystep, indepth guides
 Readily available 24/7