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How do you solve #2x+6/3 = x - 1/5#?

Answer 1

Genesis Allen

#-11/5#

#2x+6/3=x-1/5#

Subtract #x# both sides

#rarrcancel(2x)+6/3-cancelx=cancelx-1/5-cancelx#

#rarrx+6/3=-1/5#

Subtract #6/3# both sides

#rarrx+cancel(6/3)-cancel(6/3)=-1/5-6/3#

#rarrx=-1/5-6/3#

#rArrx=-1/5-2=-11/5#

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Answer 2

Eva Abramson

To solve the equation 2x + 6/3 = x - 1/5, first, we need to simplify the expression on both sides.

2x + 6/3 can be simplified to 2x + 2.

x - 1/5 remains unchanged.

So, the equation becomes:

2x + 2 = x - 1/5

Now, we can solve for x by isolating it on one side of the equation.

Subtract x from both sides:

2x - x + 2 = -1/5

This simplifies to:

x + 2 = -1/5

Now, subtract 2 from both sides:

x + 2 - 2 = -1/5 - 2

This simplifies to:

x = -1/5 - 2

Now, we can find a common denominator to combine the fractions:

x = -1/5 - 10/5

This simplifies to:

x = -11/5

Therefore, the solution to the equation 2x + 6/3 = x - 1/5 is x = -11/5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.