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How do you solve #2x² + 5x = -3#?

Answer 1

Eli Assouline

The solutions are:
# x = - 1 #

# x = - 3/2#

#2x^2 + 5x = -3#

#2x^2 + 5x + 3 = 0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:

#a=2, b= 5 , c= 3 #

The Discriminant is given by:

#Delta=b^2-4*a*c#

# = (5)^2-(4* 2 * 3 )#

# = 25 - 24 = 1 #

The solutions are normally found using the formula #x=(-b+-sqrtDelta)/(2*a)#

#x = ((-5 +-sqrt(1))/(2*2)) = (-5+-1 )/4#

The solutions are: # x = (-5+1 )/4 = -4 /4 = - 1 #

# x = (-5 - 1 )/4 = -6 /4 = - 3/2#

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Answer 2

Savannah Anderson

To solve the equation 2x² + 5x = -3, follow these steps:

Subtract -3 from both sides: 2x² + 5x + 3 = 0
Multiply each term by 2 to clear the fraction: 4x² + 10x + 6 = 0
Factor the quadratic equation: (2x + 3)(2x + 2) = 0
Set each factor equal to zero and solve for x: 2x + 3 = 0 or 2x + 2 = 0
Solve for x: x = -3/2 or x = -1

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.