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How do you solve #2x-5<x+1#?

Answer 1

You can solve it as a normal equation isolating #x# on one side (changing signs when necessary) and "reading", at the end, the result: #2x-x<5+1# #x<6# This tells you that for the first equation to be smaller than the second you cal only choose values of #x# which are #<6#. If you try, for example, #x=7# (which is bigger than #6#) you get: #2*7-5<7+1# #9<8# which is not true! Instead if you try, for example, #x=5# (which is smaller than #6#) you get: #2*5-5<5+1# #5<6# which is true!

Hope it helps!

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Answer 2

Eli Assouline

To solve the inequality 2x - 5 < x + 1, you would first subtract x from both sides to isolate the variable. Then, you would add 5 to both sides to solve for x. Finally, you would have your solution for x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #2x-5&lt;x+1#?

How do you solve #2x-5<x+1#?