How do you solve #2x-5<x+1#?

Answer 1

The answer is #x<6#.

First, you subtract #x# from both sides: #2x-5-x < x+1-x#. This is equal to #x-5 < 1#. Then, you add #5#, so on the left side there's only #x#, and on the right side there's only numbers. #x-5+5<1+5# This is equal to #x<6#, so that's the answer.

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Answer 2

Eva Abramson

To solve the inequality (2x - 5 < x + 1), follow these steps:

Subtract (x) from both sides: (2x - x - 5 < x - x + 1), which simplifies to (x - 5 < 1).
Add 5 to both sides: (x - 5 + 5 < 1 + 5), which becomes (x < 6).

So, the solution to the inequality is (x < 6).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #2x-5&lt;x+1#?

How do you solve #2x-5<x+1#?