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How do you solve #2x = 4# and #2x – y = 5#?

Answer 1

Ethan Adkins

#{(x = 2), (y = -1) :}#

Notice that you can find the value of #x# from the first equation by dividing both sides by #2#

#(color(red)(cancel(color(black)(2))) * x)/color(red)(cancel(color(black)(2))) = 4/2#

#x = color(green)(2)#

Now simply take this value of #x# and plug it into the second equation. This will allow you to find the value of #y#

#2x - y = 5#

#2 * (2) - y = 5#

#4 - y = 5#

This is equivalent to

#y = 4 -5 = color(green)(-1)#

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Answer 2

Isaiah Anthony

To solve the system of equations 2x = 4 and 2x - y = 5, you can use the method of substitution or elimination. In this case, using substitution, you can solve the first equation for x to find that x = 2. Then, substitute x = 2 into the second equation to solve for y, yielding y = -1. So, the solution to the system is x = 2 and y = -1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.