How do you solve #2x-4+7x< -6x+41#?

Answer 1
#2x-4+7x<-6x+41#
All #x# on one side numbers on another.
#2x+7x+6x<4+41#
#15x<45#
#x<45/15#
#x<3#
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Answer 2

#x<3#

We can combine the variables on the left to get

#9x-4<-6x+41#
Next, to get our variables on one side, we can add #6x# to both sides to get
#15x-4<41#
Next, add #4# to both sides to get
#15x<45#
Lastly, we divide both sides by #15# to get
#x<3#

Hope this helps!

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Answer 3

To solve the inequality 2x - 4 + 7x < -6x + 41, follow these steps:

  1. Combine like terms on both sides of the inequality: 2x + 7x + 6x < 41 + 4

  2. Simplify the equation: 15x < 45

  3. Divide both sides by 15: x < 3

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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