How do you solve #|2x - 3| = |x + 2|#?
#=> x=5
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To solve the equation |2x - 3| = |x + 2|, follow these steps:
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Set up two cases: Case 1: (2x - 3) = (x + 2) Case 2: (2x - 3) = -(x + 2)
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Solve each case separately: Case 1: 2x - 3 = x + 2 Case 2: 2x - 3 = -(x + 2)
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Solve for x in each case: Case 1: x = 5 Case 2: x = -1
So, the solutions are x = 5 and x = -1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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