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How do you solve #2x + 3\geq x - 5#?

Answer 1

See a solution process below:

Subtract #color(red)(3)# and #color(blue)(x)# from each side of the inequality to solve for #x# while keeping the inequality balanced:

#-color(blue)(x) + 2x + 3 - color(red)(3) >= -color(blue)(x) + x - 5 - color(red)(3)#

#-color(blue)(1x) + 2x + 0 >= 0 - 8#

#(-color(blue)(1) + 2)x >= -8#

#1x >= -8#

#x >= -8#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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