How do you solve #2x^2-5x=-7# using the quadratic formula?
To solve the equation 2x^2 - 5x = -7 using the quadratic formula, follow these steps:
- Identify the coefficients of the quadratic equation: a = 2, b = -5, and c = -7.
- Substitute these values into the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a).
- Calculate the discriminant (b^2 - 4ac): (-5)^2 - 4(2)(-7) = 25 + 56 = 81.
- Since the discriminant is positive (81 > 0), there are two distinct real roots.
- Plug the values into the quadratic formula: x = (-(-5) ± √81) / (2(2)).
- Simplify: x = (5 ± 9) / 4.
- Solve for both possible values of x:
- x1 = (5 + 9) / 4 = 14 / 4 = 3.5.
- x2 = (5 - 9) / 4 = -4 / 4 = -1.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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