# How do you solve #2x^2 + 5x + 5 = 0 # using the quadratic formula?

Where, a is the constant with x to the power 2. b is the constant with x to the power 1. c is the constant.

Standard Quadratic Formula:

Given Equation:

Here,

a = 2 b = 5 c = 5

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To solve the quadratic equation 2x^2 + 5x + 5 = 0 using the quadratic formula, you first identify the coefficients: a = 2, b = 5, and c = 5. Then, apply the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a). Substitute the coefficients into the formula and solve for x. The solutions will be the values of x that satisfy the equation.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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