# How do you solve #2x^2 - 15x = 8#?

The solutions are

Now let's rewrite the formula.

And contrast this with the quadratic formula.

First, we compute the discriminant.

The answers are

By signing up, you agree to our Terms of Service and Privacy Policy

To solve the equation 2x^2 - 15x = 8, you can follow these steps:

- Rewrite the equation in the standard quadratic form: 2x^2 - 15x - 8 = 0.
- Use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), where a = 2, b = -15, and c = -8.
- Plug in the values of a, b, and c into the quadratic formula.
- Calculate the discriminant, which is b^2 - 4ac.
- Determine the nature of the roots based on the discriminant:
- If the discriminant is positive, there are two real and distinct roots.
- If the discriminant is zero, there is one real root (a repeated root).
- If the discriminant is negative, there are two complex roots.

- Substitute the values of a, b, c, and the discriminant into the quadratic formula and simplify to find the solutions for x.

By signing up, you agree to our Terms of Service and Privacy Policy

- Sam and Hector are gaining weight for football season. Sam weighs 205 pounds and is gaining two pounds per week. Hector weighs 195 pounds but is gaining three pounds per week. In how many weeks will they both weigh the same amount?
- What is the axis of symmetry and vertex for the graph #y=2x^2-3x+8#?
- How do you find the standard equation given vertex at (0,-1) and passes through the point (2,2)?
- How do you solve #2x^2+3x-17=0# by completing the square?
- How do you solve #x^2+2x-3=0# using the quadratic formula?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7