How do you solve #2x^2-13x-7=0#?

Answer 1

Avery Alexander

#x = -1/2 or 7#

#2x^2-13x-7=0# can be factored to #(2x+1)(x-7)=0# set each factor equal to zero and solve for #x# #2x+1=0#

#2x+1-1=0-1#

#2x=-1#

#(cancel2x)/cancel2 =-1/2#

#x = -1/2#

#x-7=0#

#x-7+7=0+7

#x=7#

#x = -1/2 or 7#

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Answer 2

Jace Anderson

To solve the quadratic equation 2x^2 - 13x - 7 = 0, you can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a), where a = 2, b = -13, and c = -7. Plugging in these values, you'll get two solutions for x.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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