How do you solve #(2x)/1 = 1/(x-1)#?
Cross-multiply
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Multiply through by the denominator of the right-hand side and then solve the resulting quadratic equation.
Now we can use the quadratic formula (or any other method) to solve this quadratic equation.
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To solve the equation (2x)/1 = 1/(x-1), we can cross-multiply to eliminate the fractions. This gives us 2x(x-1) = 1(1), which simplifies to 2x^2 - 2x = 1. Rearranging the equation, we have 2x^2 - 2x - 1 = 0. To solve this quadratic equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac))/(2a), where a = 2, b = -2, and c = -1. Plugging in these values, we get x = (2 ± √(4 - 4(2)(-1)))/(2(2)), which simplifies to x = (2 ± √(4 + 8))/4. Further simplifying, we have x = (2 ± √12)/4, and finally x = (2 ± 2√3)/4. This can be simplified further to x = (1 ± √3)/2. Therefore, the solutions to the equation are x = (1 + √3)/2 and x = (1 - √3)/2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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