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How do you solve #-2x – 0y = -4# and #-6x – 2y = -12#?

Answer 1

Eva Abramson

#(x,y)=(2,0)#

Given [1]#color(white)("XXX")-2x-0y=-4# [2]#color(white)("XXX")-6x-2y=-12#

From [1] we have [3]#color(white)("XXX")-2x=-4#

[4]#color(white)("XXX")x=2#

Substituting #2# for #x# (from [4]) into [2] [5]#color(white)("XXX")-6(2)-2y=-12#

[6]#color(white)("XXX")-12-2y=-12#

[7]#color(white)("XXX")-2y=0#

[8]#color(white)("XXX")x=0#

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Answer 2

Eva Adamson

To solve the system of equations:

-2x - 0y = -4 -6x - 2y = -12

We can simplify the first equation to -2x = -4, which can be solved for x as follows:

-2x = -4 x = -4 / -2 x = 2

Now that we have the value of x, we can substitute it into the second equation to solve for y:

-6(2) - 2y = -12 -12 - 2y = -12

Next, add 12 to both sides of the equation to isolate the term with y:

-2y = 0

Finally, solve for y by dividing both sides by -2:

y = 0 / -2 y = 0

So, the solution to the system of equations is x = 2 and y = 0.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.