How do you solve #(2u+7)(3u-1)=0#?
#u=(-7)/2#
#u=1/3#
Given
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To solve (2u + 7)(3u - 1) = 0, you use the zero-product property. This means setting each factor equal to zero and solving for u separately.
So, you set 2u + 7 = 0 and 3u - 1 = 0, then solve for u in each equation.
For 2u + 7 = 0: 2u = -7 u = -7/2
For 3u - 1 = 0: 3u = 1 u = 1/3
Thus, the solutions are u = -7/2 and u = 1/3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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