How do you solve #2sqrt(a-1)=4sqrt(a)#?

Answer 1

#sqrt(a - 1) #= #2sqrta# Square both side: (a - 1) = 4a -> 3a = -1 -> a = -1/3 a can't be negative, then solving is impossible.

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Answer 2

Avery Alexander

To solve the equation 2√(a-1) = 4√a, we can start by squaring both sides of the equation to eliminate the square roots. This gives us 4(a-1) = 16a. Expanding and simplifying the equation, we get 4a - 4 = 16a. Rearranging the terms, we have 12a = 4. Dividing both sides by 12, we find that a = 1/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.