How do you solve #2sqrt(7x+4)-1=7#?

Answer 1

Abigail Allen

I got: #x=12/7#

I would rearrange it: #2sqrt(7x+4)=7+1# #sqrt(7x+4)=8/2# #sqrt(7x+4)=4# square both sides: #7x+4=16# #7x=16-4# #x=12/7#

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Answer 2

Savannah Anderson

To solve the equation 2√(7x+4) - 1 = 7, you can follow these steps:

Start by isolating the square root term by adding 1 to both sides of the equation: 2√(7x+4) = 8
Divide both sides of the equation by 2 to get rid of the coefficient: √(7x+4) = 4
Square both sides of the equation to eliminate the square root: 7x+4 = 16
Subtract 4 from both sides of the equation: 7x = 12
Finally, divide both sides of the equation by 7 to solve for x: x = 12/7

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.