How do you solve (2senx+1)(2cosx+3)=0 ?
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ThenTo solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( xTo solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then,To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x \To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, youTo solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ).To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you wouldTo solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). 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This leads to twoTo solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( xTo solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separateTo solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x \To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equationsTo solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x )To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equations:
To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x ) accordinglyTo solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equations:
1To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x ) accordingly.To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equations:
1.To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x ) accordingly.To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equations:

(To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x ) accordingly.To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equations:

( To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x ) accordingly.To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equations:

( 2\sin(x) + 1 = 0 )

( 2\cos(x) + 3 = 0 )
Solve each equation individually to find the values of ( x ) that satisfy the original equation.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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