How do you solve (2senx+1)(2cosx+3)=0 ?

Answer 1

Please see below.

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#(2sinx+1)(2cosx+3)=0#
#2sinx+1=0, :. sinx=-1/2, x=+-2kpi+(7pi)/6, +-2kpi+(11pi)/6#
#2cosx+3=0, :. cosx=-3/2#, this is not valid because #cosx# values are between #+1# and #-1#.
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Answer 2

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  2. ( To solve ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would first find the values of ( x ) that make each factor equal to zero individually. Then, you would solve for ( x ) accordingly.To solve the equation ( (2\sin(x) + 1)(2\cos(x) + 3) = 0 ), you would set each factor equal to zero and solve for ( x ). This leads to two separate equations:

  3. ( 2\sin(x) + 1 = 0 )

  4. ( 2\cos(x) + 3 = 0 )

Solve each equation individually to find the values of ( x ) that satisfy the original equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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