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How do you solve #2s-4.2=-8s+8#?

Answer 1

See the entire solution process below:

First, add #color(red)(4.2)# and #color(blue)(8s)# to each side of the equation to isolate the #s# term while keeping the equation balanced:

#color(blue)(8s) + 2s - 4.2 + color(red)(4.2) = color(blue)(8s) - 8s + 8 + color(red)(4.2)#

#(color(blue)(8) + 2)s - 0 = 0 + 12.2#

#10s = 12.2#

Now, divide each side of the equation by #color(red)(10)# to solve for #s# while keeping the equation balanced:

#(10s)/color(red)(10) = 12.2/color(red)(10)#

#(color(red)(cancel(color(black)(10)))s)/cancel(color(red)(10)) = 1.22#

#s = 1.22#

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Answer 2

Abigail Allen

To solve the equation ( 2s - 4.2 = -8s + 8 ), first, combine like terms on both sides. This results in ( 10s = 12.2 ). Then, divide both sides by 10 to isolate ( s ), giving ( s = \frac{12.2}{10} = 1.22 ). Therefore, the solution is ( s = 1.22 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.