How do you solve #2b + 5 = b + 7#?

Answer 1

# b = 2 #

#2b + 5 = b + 7 #
#2b - b = 7 - 5 #
# b = 2 #
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Answer 2

#2b + 5 = b + 7#
#2b = b + 2#
#b = + 2#
#b = 2#

You need all of the '#b#'s on one side of the equals sign and the numbers on the other side. To cancel out a positive from the left side (#+5#) you need to minus it. You always do the same on the opposite side that you did on the original side.

AS AN EXAMPLE.

#2b + 5 = b + 7#

The five from both sides would need to be subtracted, so...

#2b + 0 = b + 2#
Then simply minus the '#b#' from the right side and the left side so the sum changes to:
#b + 0 = 0b + 2#

After that, the zeros are eliminated, making:

#b = 2#
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Answer 3

Subtract b from both sides to get b = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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