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How do you solve #-2abs(y-7)+18=8#?

Answer 1

Eva Adamson

#y = 12# or #y = 2#

First subtract #18# from both sides #-2abs(y-7) = 8-18# #-2abs(y-7) = -10#

Then divide both sides by #-2# #abs(y-7) = 5#

Since #abs(y-7) = 5# #y-7 = 5# or #y-7 = -5# #y = 5+7# or #y = -5+7# #y = 12# or #y = 2#

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Answer 2

Ethan Adkins

To solve -2|y - 7| + 18 = 8, first, isolate the absolute value term, then solve for y.

-2|y - 7| + 18 = 8 -2|y - 7| = 8 - 18 -2|y - 7| = -10

Divide both sides by -2: |y - 7| = 5

Since the absolute value of y - 7 is equal to 5, y - 7 could be either 5 or -5.

Case 1: y - 7 = 5 y = 5 + 7 y = 12

Case 2: y - 7 = -5 y = -5 + 7 y = 2

So, the solutions are y = 12 and y = 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.