# How do you solve #|2a + 10| = | 3a - 8|#?

By signing up, you agree to our Terms of Service and Privacy Policy

To solve the equation |2a + 10| = |3a - 8|, we need to consider two cases: when the expressions inside the absolute value signs are positive and when they are negative.

Case 1: When 2a + 10 and 3a - 8 are both positive: 2a + 10 = 3a - 8

Case 2: When 2a + 10 and 3a - 8 are both negative: -(2a + 10) = -(3a - 8)

Solving each case will give us the possible values of a.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- If y varies inversely as x and y = 320 when x = 25, how do you find y when x is 40?
- How do you simplify #x^3/ (x^2-y^2) + y^3/( y^2-x^2)#?
- How do you solve #(5m)/6 + (2m)/3 = 9/2#?
- How do you combine #(4a-2)/(3a+12)-(a-2)/(a+4)#?
- What are the vertical and horizontal asymptotes of #f(x)=5/((x+1)(x-3))#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7