How do you solve #28 = 5y + 3#?
put (5y) to one side and numbers 28 and 3 on the left side and then divide the numbers onthe left side by number 5 on the right side
2.Now we divide the numbers onthe left side by number 5 on the right side 25=5y /:5 25:5=5y:5 5=y
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To solve the equation 28 = 5y + 3, you first subtract 3 from both sides to isolate the term with the variable: 28 - 3 = 5y. This gives you 25 = 5y. Then, divide both sides by 5 to solve for y: 25 ÷ 5 = y. So, y = 5.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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