How do you solve #-25( x - 4) = 55( x - 10)#?

Answer 1

#x = 8.125#

Initially, divide the multipliers among the terms enclosed in parenthesis:

#-25x + 100 = 55x - 550#
Now solve for #x# while keeping the equation balanced:
#-25x + 25x + 100 + 550 = 55x + 25x - 550 + 550#
#0 + 650 = 80x - 0#
#650 = 80x#
#650/80 = (80x)/80#
#8.125 = (cancel(80)x)/cancel(80)#
#x = 8.125#
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Answer 2

x = 8.125

-25(x-4) = 55(x-10)

First, divide the twenty-five and the fifty-five (by multiplying within parenthesis).

55x - 550 = -25x + 100

Add 550 to each side after that.

-25x plus 650 = 55x

Next, multiply both sides by 25.

650 is 80 times.

Divide 80 from both sides after that.

x = 8.125

Finally, swap 8.125 and x.

x equals 8.125

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Answer 3

To solve the equation -25(x - 4) = 55(x - 10):

  1. Distribute the constants outside the parentheses: -25x + 100 = 55x - 550

  2. Combine like terms: -25x - 55x = -550 - 100 -80x = -650

  3. Divide both sides by -80: x = (-650) / (-80)

  4. Simplify: x = 8.125

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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