How do you solve #24/5=9/(y+2)# and find any extraneous solutions?
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To solve the equation 24/5 = 9/(y + 2) and find any extraneous solutions:

Cross multiply to get rid of the fractions: (24(y + 2) = 5 \times 9).

Expand and simplify: (24y + 48 = 45).

Subtract 48 from both sides: (24y = 3).

Divide both sides by 24: (y = 3/24).

Simplify: (y = 1/8).

Check for extraneous solutions: Plug (y = 1/8) back into the original equation. (24/5 = 9/((1/8) + 2)).

Calculate: (24/5 = 9/((15/8))).

Simplify: (24/5 = 72/15).

Further simplify: (24/5 = 24/5).

Since both sides are equal, (y = 1/8) is a valid solution. No extraneous solutions.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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