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How do you solve #21>15+2a#?

Answer 1

Savannah Anderson

#a < 3#

#21 > 15 + 2a#

Subtract #color(blue)15# from both sides: #21 quadcolor(blue)(-quad15) > 15 + 2a quadcolor(blue)(-quad15)#

#6 > 2a#

Divide both sides by #color(blue)2#: #6/color(blue)2 > (2a)/color(blue)2#

#3 > a#

#a < 3#

Hope this helps!

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Answer 2

Jameson Allen

To solve the inequality 21 > 15 + 2a, you need to isolate the variable 'a'. First, subtract 15 from both sides to get 6 > 2a. Then, divide both sides by 2 to isolate 'a', resulting in 3 > a or a < 3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve #21&gt;15+2a#?

How do you solve #21>15+2a#?