How do you solve #2(x + 6)>= 3x − 2#??
Work the problem as an equation, keeping in mind the direction of the inequality symbol.
Expand the left side.
Switch sides.
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To solve (2(x + 6) \geq 3x  2), you first distribute the 2 on the left side:
[ 2x + 12 \geq 3x  2 ]
Then, you can rearrange the equation to isolate the variable (x). To do this, you can subtract (2x) from both sides:
[ 12 \geq x  2 ]
Next, add 2 to both sides to isolate (x):
[ 14 \geq x ]
So, the solution is (x \leq 14).
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To solve the inequality 2(x + 6) ≥ 3x  2:

Distribute 2 to both terms inside the parentheses: 2x + 12 ≥ 3x  2

Rearrange the equation to isolate x terms on one side: 2x  3x ≥ 2  12

Combine like terms: x ≥ 14

Divide both sides by 1 (note that dividing by a negative number reverses the inequality sign): x ≤ 14
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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