How do you solve #2(x-5)^2=30#?

Answer 1

#x=+-sqrt(15)+5#
#x~~8.87, 1.13#

First lets divide both sides by #2#, #(x-5)^2=15# Now square root both sides, #x-5=+-sqrt15# Now take away #5# from both sides, #x=+-sqrt(15)+5# Now evaluate: #x~~8.87, 1.13#

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Answer 2

Abigail Allen

To solve the equation 2(x-5)^2 = 30, follow these steps:

Divide both sides of the equation by 2 to isolate the squared term: (x-5)^2 = 15.
Take the square root of both sides of the equation: √(x-5)^2 = ±√15.
Solve for x by setting up two equations: x - 5 = ±√15.
Solve each equation separately for x:
- For x - 5 = √15, add 5 to both sides: x = 5 + √15.
- For x - 5 = -√15, add 5 to both sides: x = 5 - √15.

So, the solutions to the equation 2(x-5)^2 = 30 are x = 5 + √15 and x = 5 - √15.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.