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How do you solve #2[x-(4+2x)+3]=2x+2#?

Answer 1

Abigail Allen

You must distribute the expression.

#2[x - 4 - 2x + 3] = 2x + 2#

Distribute once more:

#2x - 8 - 4x + 6 = 2x + 2#

#2x - 2x - 4x = 2 - 6 + 8#

#-4x = 4#

#x = -1#

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Answer 2

Eva Adamson

To solve the equation 2[x-(4+2x)+3]=2x+2:

Distribute the 2 inside the brackets: 2x - 8 - 4x + 6 = 2x + 2
Combine like terms: -2x - 2 = 2x + 2
Add 2x to both sides: -2 = 4x + 2
Subtract 2 from both sides: -4 = 4x
Divide both sides by 4: x = -1

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.