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How do you solve #2(x-1) + 3= x -3(x+1)#?

Answer 1

I got
#color(white)("XXX")color(purple)(x=-1)#

1. Simplify the Left Side and Right Side Independently of Each Other #color(red)(2(x-1)+3)=color(blue)(x-3(x+1))#

#color(red)(2x-2+3)=color(blue)(x-3x-3)#

#color(red)(2x+1)=color(blue)(-2x-3)#

2. Move All the Variable (#x#) Terms to One Side and Constant Terms to the Other Adding #color(green)(2x)# to both sides: #4xcolor(red)(+1)=color(blue)(-3)#

Subtracting #color(green)(1)# from both sides: #4x=-4#

3. Reduce the Equation to a Definition of a Single Unit of the Variable (#x#) Dividing both sides by #color(green)(4)# #x=-1#

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Answer 2

Julia Adams

To solve the equation 2(x-1) + 3 = x - 3(x+1), follow these steps:

Distribute the coefficients: 2(x-1) + 3 = x - 3(x+1) 2x - 2 + 3 = x - 3x - 3
Combine like terms: 2x + 1 = x - 3x - 3
Move all x terms to one side and constants to the other: 2x - x + 3x = -1 - 3
Simplify: 4x = -4
Divide both sides by 4: x = -1

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.