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How do you solve #2(x+1)=2x+2#?

Answer 1

Ethan Adkins

Any real number or #(-oo, oo)#.

#2(x+1) = 2x + 2#

First, we want to distribute the #2# in #2(x+1)#: #2 * x = 2x#

#2 * 1 = 2#

When we combine these we get: #2x + 2#

Now let's put this back into the equation: #2x + 2 = 2x + 2#

Now subtract #2# from both sides of the equation: #2x = 2x#

Divide both sides by #2#: #x = x#

Since both sides of the equation are the same, we know that #x = x#, so the answer is any real number or #(-oo, oo)#.

Hope this helps!

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Answer 2

Eva Adamson

#"infinite solutions"#

#"note that "2(x+1)=2x+2#

#rArr2x+2=2x+2#

#"since both sides of the equation are equal then any value"# #"of x is a solution to the equation"#

#rArr" there are an infinite number of solutions"#

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Answer 3

Jace Anderson

To solve the equation 2(x + 1) = 2x + 2:

Distribute 2 across the parentheses: 2 * x + 2 * 1 = 2x + 2
Simplify both sides: 2x + 2 = 2x + 2
Subtract 2x from both sides: 2 = 2

The equation simplifies to 2 = 2, which is always true. Therefore, this equation has infinitely many solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.