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How do you solve # 2(r-3)+6=14#?

Answer 1

See a solution process below:

First, subtract #color(red)(6)# from each side of the equation to isolate the term with the parenthesis while keeping the equation balanced:

#2(r - 3) + 6 - color(red)(6) = 14 - color(red)(6)#

#2(r - 3) + 0 = 8#

#2(r - 3) = 8#

Next, divide each side of the equation by #color(red)(2)# to eliminate the parenthesis while keeping the equation balanced:

#(2(r - 3))/color(red)(2) = 8/color(red)(2)#

#(color(red)(cancel(color(black)(2)))(r - 3))/cancel(color(red)(2)) = 4#

#r - 3 = 4#

Now, add #color(red)(3)# from each side of the equation to solve for #r# while keeping the equation balanced:

#r - 3 + color(red)(3) = 4 + color(red)(3)#

#r - 0 = 7#

#r = 7#

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Answer 2

Julia Adams

To solve 2(r - 3) + 6 = 14, you first distribute the 2 to the terms inside the parentheses:

2r - 6 + 6 = 14

Then, you combine like terms:

2r = 14

Finally, you isolate the variable by dividing both sides by 2:

r = 7

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.